e^a+b=ln(x/1-x)

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Solution for e^a+b=ln(x/1-x) equation: 


D( x )

x/1-x <= 0

x/1-x <= 0

x/1-x <= 0

x-x <= 0

0 <= 0

x naleu017Cy do R

x belongs to the empty set

e^a+b = ln(x/1-x)

x belongs to the empty set

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